The magnetic field in a plane electromagnetic | vedclass

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Question

(A) The general equation for a plane electromagnetic wave is given by $B = B_{0} \sin (kx + \omega t)$.Comparing this with the given equation $B_{y} =

Vedclass · Accepted Answer

$2 	imes 10^{-3} \; m$

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(A) The general equation for a plane electromagnetic wave is given by $B = B_{0} \sin (kx + \omega t)$.Comparing this with the given equation $B_{y} = 2 	imes 10^{-7} \sin (\pi 	imes 10^{3} x + 3 \pi 	imes 10^{11} t) \; T$, we identify the wave number $k$ as:$k = \pi 	imes 10^{3} \; 	ext{rad/m}$.The relationship between the wave number $k$ and the wavelength $\lambda$ is given by $k = \frac{2\pi}{\lambda}$.Substituting the value of $k$:$\pi 	imes 10^{3} = \frac{2\pi}{\lambda}$.Solving for $\lambda$:$\lambda = \frac{2\pi}{\pi 	imes 10^{3}} = 2 	imes 10^{-3} \; m$.

The magnetic field in a plane electromagnetic wave is given by, $B_{y} = 2 \times 10^{-7} \sin (\pi \times 10^{3} x + 3 \pi \times 10^{11} t) \; T$. Calculate the wavelength.

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